Qui peut m'aider pour cette exercice de maths svp c'est vraiment URGENT !!!!!!!!!!!!!!

Salut,

Exercice 2,
1)
[tex] \frac{2x-3}{5} = \frac{1-2x}{3} \\ \frac{2x-3}{5} - \frac{1-2x}{3} = 0 \\ \frac{6x - 9 - (5 - 10x) }{15} = 0 \\ \frac{6x - 9 - 5 + 10x}{15} = 0 \\ \frac{16x - 14}{15} = 0 \\ 16x - 14 = 0 \\ 16x = 14 \\ x = \frac{14}{16} \\ x = \frac{7}{8} [/tex]
2)
[tex] \frac{x}{3} - 1 = \frac{3}{2} - \frac{3x}{4} \\ \frac{x - 3}{3} = \frac{18+9x}{12} \\ \frac{4x - 12 - 18 - 9x}{12} = 0 \\ \frac{-5x - 30}{12} = 0 \\ -5x - 30 = 0 \\ -5x = 30 \\ x = \frac{30}{-5} \\ x = -6[/tex]
3) [tex] \frac{2x - 5}{5} + \frac{2-5x}{3} = \frac{7 - x }{2} - \frac{3x - 2}{10} - \frac{1}{30}\\ \frac{12x - 30 + 20 - 50x }{30} = \frac{105 - 15x - (9x - 6) - 1}{30} \\ \frac{-38x -10}{30} = \frac{110 -24x}{30} \\ \frac{-38x - 10 - 110 + 24x}{30} = 0\\ -14x -120 = 0 \\ -14x = 120 \\ x = \frac{120}{-14} \\ x =  -\frac{60}{7} [/tex]